Knowledge base
Why do you charge the IOPS disk operations?
Posted by on 03.01.2013 18:50

Hard disk capacity is expressed in gigabytes, but how to define its performance? Well, we can achieve it with the help of the parameter called IOPS (Input / Output Operations Per Second), which defines the number of read and write operations which disk drive can make per second.

Now try to imagine the situation where a single server with certain number of hard drives runs many environments assigned to different clients. This context can easily lead to the situation where one customer overloads the whole environment, slowing or even making impossible proper server work for other clients.

Therefore, the real cloud environment, in order to keep the quality of services and ensure customer billing by actually used resources, simply need to control the number of IOPS performed within the context of each client.

Another advantage of the IOPS settlement is the guarantee of drives productivity. Traditional disk (SATA 7200 rpm) supports about 100 - 200 IOPS, Oktawave offers disks whose parameters is in the range from 1000 IOPS - up to 1 000 000 IOPS.

We also recommend you an individual expected costs calculation that you can face in a particular environment. Very often you can come across imperceptible costs, which begin to be important only in case of large and demanding server farms.

For example, a popular website, such as, generates about 18 million monthly IOPS, which is equivalent to 0.20 USD per month.
Drive up burdening Tier-1 class, which takes up to one thousand IO operations per second (which is equivalent to about five hard drives SAS or FC operating in RAID or array), can be performed within one month of operations 2,592 million. It would be a charge equal to 30 USD. And this is the maximum monthly payment for disk IOPS Tier-1 connected to the instance (server).

Of course, the disk class Tier-2 and Tier-5 can perform much more operations than the Tier-1 and then the fee will be correspondingly greater.

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